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Once the location of a page has changed, or the page has reloaded, it loses all knowledge about any windows it may have opened. Therefoe code to detect whether the popup window is still open will not work.
The only workaround is to use a frameset with a hidden frame and to open the popup window from the parent frameset. This way the reference to the popup window is preserved even if one of the frames is reloaded.
<HTML>
<HEAD>
<SCRIPT LANGUAGE="JavaScript"><!--
function openWindow() {
if (!window.window2) {
// has not yet been defined
window2 = window.open('apage.html','windowRef','width=100,height=100');
}
else {
// has been defined
if (!window2.closed) {
// still open
window2.focus();
}
else {
window2 = window.open('apage.html','windowRef','width=100,height=100');
}
}
}
openWindow()
//--></SCRIPT>
</HEAD>
<FRAMESET COLS="100%,*">
<FRAME SRC="apage.html">
<FRAME SRC="bpage.html">
</FRAMESET>
</HTML>If need be you can then invoke the parents openWindow() function from one of the frames to reopen the window if you think it may have been closed, with: parent.openWindow().
the following was submitted anonymously:
I don't use frames, below is the code I use. The parent window can check to see if the daughter window is already open or don't allow the daughter window to lose focus "focus"...
In the parent window open the daughter window with the following code:
var daughterWindow = null;
function openBrowser(f,p,t) {
//f = path to file
//p = parameters
//t = title - optional this identifies the daughterwindow
if (!daughterWindow || daughterWindow.closed) {
daughterWindow = window.open(f,t,p);
} else {
alert("Close any other open daughter windows!");
}
}
function handleSetFocusToDW() {
//set this function to fire on the document.onfocus() event so daughter window can't loose focus
if (daughterWindow) {
if (!daughterWindow.closed) {
daughterWindow.focus();
}
}
}