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irt.org FAQ Knowledge Base Q1310
Sent by
Mauricio Zuluaga on September 09, 2002 at 11:55:00:
Comments:
Reading at the documentation for RegExp I found that the replace method returns a new string. It doesn't modify the string that invokes the method.
I change the trim function to this in order to make it work:
function trim(str)
{
var newString = str.replace(/^\s*/, '').replace(/\s*$/, '');
return newString;
}
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